Armed Forces Classification Test (AFCT) Arithmetic Reasoning Practice Test

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The population of Small town, Texas increased by 5% between 1985 and 1990. If the population was 210 in 1990, what was the population in 1985?

190 people
200 people
210 people
220 people

The correct answer is: 200 people

To determine the population of Small town, Texas in 1985 based on the information given, we start with the known population in 1990, which is 210. The problem states that the population increased by 5% over the five years between 1985 and 1990. To find the population in 1985, we can set up the relationship based on the percentage increase. A 5% increase means that the population in 1985 multiplied by 1.05 will equal the population in 1990. We can express this mathematically: Let the population in 1985 be represented as $ P $. According to the problem, we have: \[ P \times 1.05 = 210 \] To find $ P $, we rearrange the equation: \[ P = \frac{210}{1.05} \] Now, performing the calculation: \[ P = \frac{210}{1.05} = 200 \] This calculation reveals that the population in 1985 was 200 people. This is the correct answer because it accurately reflects the initial population before the 5% increase in value led to the 1990 population of 210. The multiplication by